2x^2-14x+20=-0,75x^2+6x-9

Solution for 2x^2-14x+20=-0,75x^2+6x-9 equation:

2x^2-14x+20=-0.75x^2+6x-9

We move all terms to the left:

2x^2-14x+20-(-0.75x^2+6x-9)=0

We get rid of parentheses

2x^2+0.75x^2-6x-14x+9+20=0

We add all the numbers together, and all the variables

2.75x^2-20x+29=0

a = 2.75; b = -20; c = +29;
Δ = b2-4ac
Δ = -202-4·2.75·29
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-9}{2*2.75}=\frac{11}{5.5}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+9}{2*2.75}=\frac{29}{5.5}
=5+1/3.66666666667
$